Integrand size = 59, antiderivative size = 95 \[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=\frac {\sqrt {b+\sqrt {b^2-4 a c}} E\left (\arcsin \left (\frac {\sqrt {2} \sqrt {c} x}{\sqrt {b+\sqrt {b^2-4 a c}}}\right )|-\frac {b+\sqrt {b^2-4 a c}}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {2} \sqrt {c}} \]
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Time = 0.10 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.017, Rules used = {435} \[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=\frac {\sqrt {\sqrt {b^2-4 a c}+b} E\left (\arcsin \left (\frac {\sqrt {2} \sqrt {c} x}{\sqrt {b+\sqrt {b^2-4 a c}}}\right )|-\frac {b+\sqrt {b^2-4 a c}}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {2} \sqrt {c}} \]
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Rule 435
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {b+\sqrt {b^2-4 a c}} E\left (\sin ^{-1}\left (\frac {\sqrt {2} \sqrt {c} x}{\sqrt {b+\sqrt {b^2-4 a c}}}\right )|-\frac {b+\sqrt {b^2-4 a c}}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {2} \sqrt {c}} \\ \end{align*}
Time = 2.24 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=\frac {\sqrt {b+\sqrt {b^2-4 a c}} E\left (\arcsin \left (\frac {\sqrt {2} \sqrt {c} x}{\sqrt {b+\sqrt {b^2-4 a c}}}\right )|-\frac {b+\sqrt {b^2-4 a c}}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {2} \sqrt {c}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(808\) vs. \(2(80)=160\).
Time = 2.89 (sec) , antiderivative size = 809, normalized size of antiderivative = 8.52
method | result | size |
elliptic | \(\frac {\sqrt {\frac {-2 c \,x^{2}+\sqrt {-4 a c +b^{2}}-b}{-b +\sqrt {-4 a c +b^{2}}}}\, \left (-b +\sqrt {-4 a c +b^{2}}\right ) \sqrt {-\frac {\left (-2 c \,x^{2}+\sqrt {-4 a c +b^{2}}-b \right ) \left (-2 c \,x^{2}+\sqrt {-4 a c +b^{2}}+b \right )}{a c}}\, \left (\frac {\sqrt {2}\, \sqrt {1-\frac {2 c \,x^{2}}{-b +\sqrt {-4 a c +b^{2}}}}\, \sqrt {1-\frac {2 c \,x^{2}}{b +\sqrt {-4 a c +b^{2}}}}\, F\left (x \sqrt {2}\, \sqrt {\frac {c}{-b +\sqrt {-4 a c +b^{2}}}}, \frac {\sqrt {-4+\frac {2 \left (-\frac {2 c}{b +\sqrt {-4 a c +b^{2}}}+\frac {2 c}{b -\sqrt {-4 a c +b^{2}}}\right ) \left (b -\sqrt {-4 a c +b^{2}}\right )}{c}}}{2}\right )}{2 \sqrt {\frac {c}{-b +\sqrt {-4 a c +b^{2}}}}\, \sqrt {1-\frac {2 c \,x^{2}}{b +\sqrt {-4 a c +b^{2}}}+\frac {2 c \,x^{2}}{b -\sqrt {-4 a c +b^{2}}}-\frac {4 c^{2} x^{4}}{\left (b -\sqrt {-4 a c +b^{2}}\right ) \left (b +\sqrt {-4 a c +b^{2}}\right )}}}+\frac {2 c \sqrt {2}\, \sqrt {1-\frac {2 c \,x^{2}}{-b +\sqrt {-4 a c +b^{2}}}}\, \sqrt {1-\frac {2 c \,x^{2}}{b +\sqrt {-4 a c +b^{2}}}}\, \left (F\left (x \sqrt {2}\, \sqrt {\frac {c}{-b +\sqrt {-4 a c +b^{2}}}}, \frac {\sqrt {-4+\frac {2 \left (-\frac {2 c}{b +\sqrt {-4 a c +b^{2}}}+\frac {2 c}{b -\sqrt {-4 a c +b^{2}}}\right ) \left (b -\sqrt {-4 a c +b^{2}}\right )}{c}}}{2}\right )-E\left (x \sqrt {2}\, \sqrt {\frac {c}{-b +\sqrt {-4 a c +b^{2}}}}, \frac {\sqrt {-4+\frac {2 \left (-\frac {2 c}{b +\sqrt {-4 a c +b^{2}}}+\frac {2 c}{b -\sqrt {-4 a c +b^{2}}}\right ) \left (b -\sqrt {-4 a c +b^{2}}\right )}{c}}}{2}\right )\right )}{\left (-b +\sqrt {-4 a c +b^{2}}\right ) \sqrt {\frac {c}{-b +\sqrt {-4 a c +b^{2}}}}\, \sqrt {1-\frac {2 c \,x^{2}}{b +\sqrt {-4 a c +b^{2}}}+\frac {2 c \,x^{2}}{b -\sqrt {-4 a c +b^{2}}}-\frac {4 c^{2} x^{4}}{\left (b -\sqrt {-4 a c +b^{2}}\right ) \left (b +\sqrt {-4 a c +b^{2}}\right )}}\, \left (-\frac {2 c}{b +\sqrt {-4 a c +b^{2}}}+\frac {2 c}{b -\sqrt {-4 a c +b^{2}}}-\frac {b}{a}\right )}\right )}{2 \sqrt {\frac {-2 c \,x^{2}+\sqrt {-4 a c +b^{2}}+b}{b +\sqrt {-4 a c +b^{2}}}}\, \left (-2 c \,x^{2}+\sqrt {-4 a c +b^{2}}-b \right )}\) | \(809\) |
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Leaf count of result is larger than twice the leaf count of optimal. 318 vs. \(2 (77) = 154\).
Time = 0.14 (sec) , antiderivative size = 318, normalized size of antiderivative = 3.35 \[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=-\frac {2 \, \sqrt {\frac {1}{2}} {\left (\sqrt {b^{2} - 4 \, a c} b x + {\left (b^{2} - 2 \, a c\right )} x\right )} \sqrt {\frac {b + \sqrt {b^{2} - 4 \, a c}}{c}} \sqrt {-\frac {c}{a}} E(\arcsin \left (\frac {\sqrt {\frac {1}{2}} \sqrt {\frac {b + \sqrt {b^{2} - 4 \, a c}}{c}}}{x}\right )\,|\,-\frac {b^{2} - 2 \, a c - \sqrt {b^{2} - 4 \, a c} b}{2 \, a c}) - 2 \, \sqrt {\frac {1}{2}} {\left (\sqrt {b^{2} - 4 \, a c} {\left (b - c\right )} x + {\left (b^{2} - {\left (2 \, a - b\right )} c\right )} x\right )} \sqrt {\frac {b + \sqrt {b^{2} - 4 \, a c}}{c}} \sqrt {-\frac {c}{a}} F(\arcsin \left (\frac {\sqrt {\frac {1}{2}} \sqrt {\frac {b + \sqrt {b^{2} - 4 \, a c}}{c}}}{x}\right )\,|\,-\frac {b^{2} - 2 \, a c - \sqrt {b^{2} - 4 \, a c} b}{2 \, a c}) + {\left (b c + \sqrt {b^{2} - 4 \, a c} c\right )} \sqrt {\frac {b x^{2} + \sqrt {b^{2} - 4 \, a c} x^{2} + 2 \, a}{a}} \sqrt {-\frac {b x^{2} - \sqrt {b^{2} - 4 \, a c} x^{2} - 2 \, a}{a}}}{4 \, c^{2} x} \]
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\[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=\int \frac {\sqrt {\frac {b + 2 c x^{2} - \sqrt {- 4 a c + b^{2}}}{b - \sqrt {- 4 a c + b^{2}}}}}{\sqrt {- \frac {- b + 2 c x^{2} - \sqrt {- 4 a c + b^{2}}}{b + \sqrt {- 4 a c + b^{2}}}}}\, dx \]
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\[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=\int { \frac {\sqrt {\frac {2 \, c x^{2}}{b - \sqrt {b^{2} - 4 \, a c}} + 1}}{\sqrt {-\frac {2 \, c x^{2}}{b + \sqrt {b^{2} - 4 \, a c}} + 1}} \,d x } \]
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Exception generated. \[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}}}{\sqrt {1-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx=\int \frac {\sqrt {\frac {2\,c\,x^2}{b-\sqrt {b^2-4\,a\,c}}+1}}{\sqrt {1-\frac {2\,c\,x^2}{b+\sqrt {b^2-4\,a\,c}}}} \,d x \]
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